25c^2-25c-50=0

Solution for 25c^2-25c-50=0 equation:

Simplifying
25c2 + -25c + -50 = 0

Reorder the terms:
-50 + -25c + 25c2 = 0

Solving
-50 + -25c + 25c2 = 0

Solving for variable 'c'.

Factor out the Greatest Common Factor (GCF), '25'.
25(-2 + -1c + c2) = 0

Factor a trinomial.
25((-1 + -1c)(2 + -1c)) = 0

Ignore the factor 25.
Subproblem 1
Set the factor '(-1 + -1c)' equal to zero and attempt to solve:

Simplifying
-1 + -1c = 0

Solving
-1 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + -1c = 0 + 1

Combine like terms: -1 + 1 = 0
0 + -1c = 0 + 1
-1c = 0 + 1

Combine like terms: 0 + 1 = 1
-1c = 1

Divide each side by '-1'.
c = -1

Simplifying
c = -1
Subproblem 2
Set the factor '(2 + -1c)' equal to zero and attempt to solve:

Simplifying
2 + -1c = 0

Solving
2 + -1c = 0

Move all terms containing c to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -1c = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -1c = 0 + -2
-1c = 0 + -2

Combine like terms: 0 + -2 = -2
-1c = -2

Divide each side by '-1'.
c = 2

Simplifying
c = 2
Solution
c = {-1, 2}